(z^2+1)(-2z^2+3z-2)=0

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Solution for (z^2+1)(-2z^2+3z-2)=0 equation: 


Simplifying
(z2 + 1)(-2z2 + 3z + -2) = 0

Reorder the terms:
(1 + z2)(-2z2 + 3z + -2) = 0

Reorder the terms:
(1 + z2)(-2 + 3z + -2z2) = 0

Multiply (1 + z2) * (-2 + 3z + -2z2)
(1(-2 + 3z + -2z2) + z2(-2 + 3z + -2z2)) = 0
((-2 * 1 + 3z * 1 + -2z2 * 1) + z2(-2 + 3z + -2z2)) = 0
((-2 + 3z + -2z2) + z2(-2 + 3z + -2z2)) = 0
(-2 + 3z + -2z2 + (-2 * z2 + 3z * z2 + -2z2 * z2)) = 0
(-2 + 3z + -2z2 + (-2z2 + 3z3 + -2z4)) = 0

Combine like terms: -2z2 + -2z2 = -4z2
(-2 + 3z + -4z2 + 3z3 + -2z4) = 0

Solving
-2 + 3z + -4z2 + 3z3 + -2z4 = 0

Solving for variable 'z'.

The solution to this equation could not be determined.

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